1. Set up a punnett square using the following information:
•
Dominate allele for tall plants = D
Recessive allele for dwarf plants = d
Dominate allele for purple flowers = W
Recessive allele for white flowers = w
Cross a homozygous dominate parent
•
(DDWW) with a homozygous recessive parent
(ddww)
DW DW
DW DW
All will
dw AdWw Ad Ww
dwDd Ww Ad W
dw Dd Ww DJ Ww
dw Ad Ww Dd Ww
3. Set up a punnett square using the following
information:
Dihybrid Cross Worksheet
for each
be Ad Ww
Dominate allele for black fur in guinea pigs = B
Recessive allele for white fur in guinea pigs =b
Dominate allele for rough fur in guinea pigs =
R
Recessive allele for smooth fur in guinea pigs
=r
Cross a heterozygous parent (BbRr) with a
heterozygous parent (BbRr)
BR Br bR br
BR BBRR BB Rr Bb RR Bb Rr
Br BB Rr BB rr Bb Rr Bb rr
OR BbRR BbRr
bb RR bb Rr
br Bb Rr Bb rr bb Rr bb rr
BbRr
X
Bb Rr
4 Possible 1. BR
1. BR
2. Br
Gametes
2. Br
3. bR
3. bR
4. br
4. br
Page 1
2. Using the punnett square in question #1:
a.
What is the probability of producing tall plants with
purple flowers? 100% 0
Possible genotype(s)? DdWw
or 16/16
b. What is the probability of producing dwarf plants
with white flowers? 0%
Possible genotype(s)?
None
C.
What is the probability of producing tall plants with
white flowers? 0%
Possible genotype(s)?
None
d. What is the probability of producing dwarf plants
with purple flowers?
0%
Possible genotype(s)?
None
4. Using the punnett square in question #3:
What is the probability of producing guinea
pigs with black, rough fur? q
a.
9/16
Possible genotype(s)?
BBRR BBR BbRR
BbRr
b. What is the probability of producing guinea
pigs
3/16
with black, smooth fur?
Possible genotype(s)?
C.
BB rr Bbrr
What is the probability of producing guinea
with white, rough fur?
pigs
3/16
Possible genotype(s)?
bb RR bbRr
d. What is the probability of producing guinea
pigs
with white, smooth fur?
1/16
Possible genotype(s)?
bbrr
La
Pane
Dominate allele for purple corn kernels = R
Recessive allele for yellow corn kernels = r
Dominate allele for starchy kernels = T
Recessive allele for sweet kernals = t
Cross a homozygous dominate parent with a
homozygous recessive parent
RT RT
RT
R+
RT
It
rt
Rr Tz
100%
Using the punnett square in question #5:
a. What is the probability of producing purple,
starchy
100%
corn kernels?
Possible genotype(s)?
RITE
b. What is the probability of producing yellow,
starchy corn kernels? 0%
Possible genotype(s)?
None
C. What is the probability of producing purple, sweet
corn kernels?
Oi.
Possible genotype(s)?
None
d. What is the probability of producing yellow, sweet
corn kernels?
0%
Possible genotype(s)?
None
RRTT x rritt
5. Set up a punnett square using the following
information:
rt
H
����
2
7. Set up a punnett square using the following
information:
Dominate allele for normal coat color in wolves =
N
•
Recessive allele for black coat color in wolves =
n
•
Dominant allele for brown eyes = B
Recessive allele for blue eyes = b
Cross a heterozygous parent with a
heterozygous parent
NB
Nb
nB
B nb
NB
Nb
nB
nb
8. Using the punnett square in question #7:
a. What is the probability of producing a wolf with a
normal coat color with brown eyes?
9/16
Possible genotype(s)?
NBB NnBB
b. What is the probability of producing
normal coat color with blue eyes?
NN Bb
a wolf with a
3/16
Possible genotype(s)?
i NNbb
Nn bb
C.
What is the probability of producing a wolf with
a black coat with brown eyes?
3/16
Possible genotype(s)?
Bb
��ڧ� ��
nn
What is the probability of producing a wolf with
a black coat with blue eyes?
//16
Possible genotype(s)?
nnbb
Heterozygous
Nn Bb
خور
#9
#10
a)
+)
a) p)
F₁)
Dominant Tall, Axial
~
Recessive
Short; Terminal
P
�ܧ�
_��
Tall + Terminal
TT aa
मैं Teta
c) Tt Au x Tt Aa
Tz
a a x Aa
Litter #1
3 Aa
2
Ga
Litter #2
4 aa
2 Aa
X Short & Axial
tt AA
X
Tall + Axial
Tt Aa
9:3:3:1 Ratio
9
3-
- Tall & Axial (9/16)
Tall + Terminal (1/16)
Short & Axial (1/16)
Short+ Terminal (1/16)
3
1
A_ curly
brown
aa
T_A_
T_aa
tt -
ttaa
오
Page 3
aq
-18
नत
नत
2
aq
-الو
2
11
1/16
#11
{
#12
a)
Page 4
Woman Q Aatt
X
4 Possible Genotypes
A a Tt
A a tt
Tt
aa
aatt
HHRR x hhrr
all F. Hh Rr
b) hh RR x HH rr
all F, Hh Rr
��
Same
as
c) p: hhrr X
P:
F,:
2 hh R
GINNING
2 H_R_
1
H_rr
Part A
aa Tt
�� Husband
Hh Rr x Hh Rr
F₂-
2
9:3:3:1 Ratio
9
H_R
3 H _ rr
3 h h R
1
hh rr
07 Must be Hh Rr
Possible
P: hhrr x Hh Rr
Hh Rr
F,
Hhrr
genotypes (4)
hh Rr
hhrr
